Mathematics
If O is any point inside △ABC, prove that ∠BOC > ∠A.
Triangles
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Answer

Join OA, OB and OC, produce OA to meet BC at D.
In △AOB,
∠BOD > ∠BAO …..(1) (Exterior angle is greater than interior opposite angle)
In △AOC,
∠COD > ∠CAO …..(2) (Exterior angle is greater than interior opposite angle)
Adding eq.(1) and (2), we have:
∠BOD + ∠COD > ∠BAO + ∠CAO
⇒ ∠BOC > ∠BAC
⇒ ∠BOC > ∠A.
Hence, proved that ∠BOC > ∠A.
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