The salt which in solution gives a pale green precipitate with sodium hydroxide solution and a white precipitate with barium chloride solution is:

1. Iron (III) sulphate
2. Iron (II) sulphate
3. Iron (II) chloride
4. Iron (III) chloride

Iron (II) sulphate

Reason — Iron (II) sulphate (FeSO₄) reacts with NaOH to give pale green precipitate of ferrous hydroxide.

$\underset{\text{pale green solution}}{{\text{FeSO}$4}} + 2\text{NaOH} \longrightarrow \underset{\text{dirty green ppt}}{\text{Fe(OH)}2↓} + \underset{\text{colourless in solution}}{\text{Na}2\text{SO}4}

The sulphate ion (SO₄^2-) from FeSO₄ reacts with BaCl₂ to form, white precipitate of BaSO₄

Ba²⁺ + SO₄^2- ⟶ BaSO₄