Chemistry
The statements below show the results when three metal strips, P, Q, and R, are placed in blue copper sulphate solution.
P — Solution turns green. Q — Solution becomes colourless. R — Solution remains blue.
Which of the following metals could be P, Q, and R?
- P-Al, Q-Zn, R- Fe
- P-Zn, Q-Fe, R- Ag
- P-Fe, Q-Zn, R-Ag
- P- Zn, Q-AI, R– Fe
Electrolysis
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Answer
P-Fe, Q-Zn, R-Ag
Reason — P is Fe and Q is Zn, because they are more reactive and present above Cu in activity series, so Fe and Zn displace Cu2+ and forms Fe2+ and Zn2+ respectively. Fe2+ gives pale green colour and the blue colour fades when Zn displaces Cu.
R is Ag, as it is less reactive than Cu and cannot displace Cu, so solution stays blue.
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