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Mathematics

The mean of the following distribution is 52 and the frequency of class-interval 30 - 40 is 'f'. Find 'f'.

Class IntervalFrequency
10 - 205
20 - 303
30 - 40f
40 - 507
50 - 602
60 - 706
70 - 8013

Measures of Central Tendency

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Answer

Class IntervalClass mean (x)Frequency (f)fx
10 - 2015575
20 - 3025375
30 - 4035f35f
40 - 50457315
50 - 60552110
60 - 70656390
70 - 807513975
TotalΣf = 36 + f1940 + 35f

By formula,

⇒ Mean = ΣfxΣf\dfrac{Σfx}{Σf}

⇒ 52 = 1940+35f36+f\dfrac{1940 + 35f}{36 + f}

⇒ 52(36 + f) = 1940 + 35f

⇒ 1872 + 52f = 1940 + 35f

⇒ 52f - 35f = 1940 - 1872

⇒ 17f = 68

⇒ f = 6817\dfrac{68}{17} = 4.

Hence, f = 4.

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