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Mathematics

Using standard formulae, expand each of the following:

(i) (5x - 3y)2

(ii) (3a - 7b)2

(iii) (12x32y)2\Big(\dfrac{1}{2}x - \dfrac{3}{2}y\Big)^2

Expansions

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Answer

We know that,

⇒ (a - b)2 = a2 + b2 - 2ab.

(i) Given,

⇒ (5x - 3y)2

⇒ (5x)2 + (3y)2 - 2 × 5x × 3y

⇒ 25x2 + 9y2 - 30xy

Hence, (5x - 3y)2 = 25x2 + 9y2 - 30xy .

(ii) Given,

⇒ (3a - 7b)2

⇒ (3a)2 + (7b)2 - 2 × 3a × 7b

⇒ 9a2 + 49b2 - 42ab

Hence, (3a - 7b)2 = 9a2 + 49b2 - 42ab.

(iii) Given,

(12x  32y)2(12x)2+(32y)22×12x×32yx24+94y232xy\Rightarrow \Big(\dfrac{1}{2}x\ -\ \dfrac{3}{2}y\Big)^2 \\[1em] \Rightarrow \Big(\dfrac{1}{2}x\Big)^2 + \Big(\dfrac{3}{2}y\Big)^2 - 2 \times \dfrac{1}{2}x \times \dfrac{3}{2}y \\[1em] \Rightarrow \dfrac{x^2}{4} + \dfrac{9}{4}y^2 - \dfrac{3}{2}xy

Hence, (12x32y)2=x24+94y232xy\Big(\dfrac{1}{2}x - \dfrac{3}{2}y\Big)^2 = \dfrac{x^2}{4} + \dfrac{9}{4}y^2 - \dfrac{3}{2}xy.

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