Physics
The adjacent diagram represents a glass slab of refractive index 1.5. If PA, PB, PC and PD represent the rays of light from a point P at the bottom of the block, draw the approximate directions of these rays as they emerge out of the glass slab. (sin 42° = 2/3)

Refraction Plane Surfaces
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Answer
Given,
Refractive index of glass with respect to air = aμg = 1.5 =
Angle made by PA with normal = 0°
Angle made by PB with normal = 30°
Angle made by PC with normal = 42°
Angle made by PD with normal = 60°
sin 42° = 2/3

(i) For ray PA
i = 0°
⟹ r = sin-1(0) = 0°
Ray PA will not deviate and emerge straight.
(ii) For PB
i = 30°
⟹ r = sin-1(0.75) ≈ 49°
Ray PB will emerge at an angle of 49° with the normal.
(iii) For PC
i = 42°
⟹ r = sin-1(1) = 90°
This is the condition for critical angle.
Ray PC will graze along the surface.
(iv) For PD
i = 60°
Here,
sin r > 1 which a condition of total internal reflection.
Ray PD will suffer total internal reflection.
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