Chemistry
The diagram below shows a circuit used to electrolyse aqueous sodium argento cyanide. Which arrow indicates the movement of the silver ions in the electrolyte and of the electrons in the external circuit?
| Silver ions | Electrons | |
|---|---|---|
| 1. | 3 | 1 |
| 2. | 3 | 2 |
| 3. | 2 | 4 |
| 4. | 4 | 1 |
Electrolysis
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Answer
4,1
Reason — The silver ions are released and passed into solution from the active anode electrode, and they migrate towards the cathode. Hence, the direction of movement of silver ions will be 4.
The direction of current in the external circuit will be from positive terminal of the power supply to the negative terminal. The movement of electrons in the external circuit will in the opposite direction of current. Hence, the direction of movement of electrons is 1.
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